Chemistry - Electrochemistry Question with Solution | TestHub

$\text{K}=\frac{1}{\text{R}}\left(\frac{\mathit{\text{l}}}{\text{a}}\right)$

${\text{K}}_{\left(\text{0.2 M}\right)}=\frac{1}{50}\left(\frac{\mathit{\text{l}}}{\text{a}}\right)$...... (I)

${\text{K}}_{\left(\text{0.5 M}\right)}=\frac{1}{280}\left(\frac{\mathit{\text{l}}}{\text{a}}\right)$...... (II)

$\frac{{\text{K}}_{\left(\text{0.5 M}\right)}}{{\text{K}}_{\left(\text{0.2 M}\right)}}=\frac{1}{280}\times 50$

${\text{K}}_{\left(\text{0.5 M}\right)}=\frac{\text{1.4}}{280}\times 50=\frac{1}{4}$

${\Lambda }_{\text{m}}=\frac{\text{K}}{\text{C}}=\frac{1}{4}\times \frac{1}{\text{0.5}\times 10^3}=5\times 10^{-4}{\mathrm{ \Omega }}^{-1}{m}^2{\text{mol}}^{-1}$

$\left(\text{C}={\text{concentration in mol/m}}^3=\text{0.5}\times 10^3{moles/m}^3\right)$