Chemistry - Electrochemistry Question with Solution | TestHub

p)  (C₂H₅)₃N added to CH₃COOH
(C₂H₅)₃NH⁺and CH₃COO^-ions generated in solution, conductivity increases & then remains constant as (C₂H₅)₃N is not dissociated when in excess.

q)  KI_eqadded to AgNO₃
$\left[{\text{Ag}}_{\text{(aq)}}^{+}+{\text{NO}}_{3\text{(aq)}}^{-}\right]+\text{KI}⟶\left[{\text{K}}_{\text{(aq)}}^{+}+{\text{NO}}_{3\text{(aq)}}^{-}\right]+\text{AgI}$
$\left({\text{Ag}}^{+}\&{\text{NO}}_3^{-}\right)$ions replaced by$\left({\text{K}}_{\text{(aq)}}^{+}\&{\text{NO}}_{3\text{(aq)}}^{-}\right)$
conductivity does not change till complete precipitation but later on with additional KI_(aq)added conductivity will increase.

r)  On addition of acetic acid to KOH. KOH fully dissociated replaced by
${\text{CH}}_3\text{COOH}+\left({\text{K}}^{+}+{\text{OH}}^{-}\right)⟶\left[{\text{CH}}_3{\text{COO}}^{-}+{\text{K}}^{+}\right]+{\text{H}}_2\text{O}$
The net result is replacement of OH^-by CH₃COO^-ions whose ionic mobility is less so conductivity will decrease first and then will not change much due to addition of CH₃COOH(in excess) which will not be dissociated

s)  On addition of NaOH to HI$\left({\text{H}}_{\text{(aq)}}^{+}+{\text{I}}_{\text{(aq)}}^{-}\right)+\text{NaOH}⟶\left({\text{Na}}^{+}+{\text{I}}^{-}\right)+{\text{H}}_2\text{O}$
there will be replacement of H⁺by Na⁺whose mobility is less than H⁺which means conductivity will decrease first & then due to adding NaOH which is a strong electrolyte which fully dissociates, so conductivity will increase.