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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsHard2 minPYQ_2013

ChemistryHardsingle choice

A current of 2.0 A passed for 5 hours through a molten metal salt deposits $22.2 g$ of metal (At wt. $= 177$ ). The oxidation state of the metal in the metal salt is

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Answer:

Solution:

$m = \frac{E \cdot wt \times Q}{96500}$ $∴ E . wt = \frac{22.2 \times 96500}{2 \times 5 \times 60 \times 60} = 60.3 = \frac{m \times 96500}{Q}$ Oxidation state $= \frac{At wt.}{Eq. wt.} = \frac{177}{60.3} = 3$

Stream:BITSATSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2013

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