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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2011

ChemistryMediumsingle choice

The number of coulombs required for the deposition of $108 g$ of silver is

Answer:

Solution:

Amt. deposited $= \frac{E. wt \times Q}{96500}$ ; $107.870 = \frac{107.870}{96500} \times Q; ∴ Q = 96500 C$

Stream:BITSATSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2011

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