Question: For the above cell | TestHub

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Paragraph:The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal $M$ is :

M (s) ∣ M^{+} (α q; 0.05 molar) ∥ M^{+} (a q; 1 molar) ∣ M (s)

For the above electrolytic cell the magnitude of the cell potential $∣ E_{cell} ∣ = 70 mV$ .

Question:For the above cell

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Answer:

B

Solution:

The given cell is electrolytic concentration cell, So $E_{cell}^{\circ} = 0$ Anode : $M (s) ⟶ M^{+} (a q) + e^{-} Cathode : M^{+} (a q) + e^{-} ⟶ M (s) M^{+} (a q) cathode ⇌ M^{+} (a q) anode E_{cell} = E_{cell}^{\circ} - \frac{0.0591}{1} lo g \frac{[ M ^{+} ] _{anodic}}{[ M ^{+} ] _{cathodic}} = 0 - \frac{0.0591}{1} lo g \frac{0.05}{1} E_{cell} = 70 mV (+ ve) Hence, Δ G = - n F E_{cell} = - ve$

Stream:JEE_ADVSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2010

Chemistry - Electrochemistry Question with Solution | TestHub

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