The ionization constant of ammonium hydroxide is 1.77 × 1 0 − 5 at 298 K . Hydrolysis constant of ammonium chloride -NEET 2009 (Mains)

K h = K b K W = 1.77 × 1 0 − 5 1 0 − 14 = 5.65 × 1 0 − 10

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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2009

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The ionization constant of ammonium hydroxide is $1.77 \times 1 0^{- 5}$ at $298 K$ . Hydrolysis constant of ammonium chloride -NEET 2009 (Mains)

Answer:

Solution:

$K_{h} = \frac{K _{W}}{K _{b}} = \frac{1 0 ^{- 14}}{1.77 \times 1 0 ^{- 5}} = 5.65 \times 1 0^{- 10}$

Stream:NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2009

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