Chemistry - Electrochemistry Question with Solution | TestHub

${\mathrm{H}}^{+}+\underset{1\mathrm{F}}{e^{-}}⟶\frac{1}{2}{\mathrm{H}}_2$ At STP, $\because 96500\mathrm{C}$ liberates $=11.2\mathrm{L}{\mathrm{H}}_2$ $\therefore 10\times 80\times 60\mathrm{C}$ will liberate $$\begin{array}{rl}& =\frac{11.2\times 10\times 80\times 60}{96500}\mathrm{L}{\mathrm{H}}_2\\ =& 5.57\mathrm{L}\text{ hydrogen gas }\end{array}$$