Chemistry - Electrochemistry Question with Solution | TestHub

For the reduction of ${\mathrm{NO}}_3^{-}$ion in an aqueous solution $E^{\circ }$ is $+0.96\mathrm{V}$. Values of $E^{\circ }$ for some metal ions are given below. $$\begin{array}{rl}& {\mathrm{V}}^{2+}(aq)+2e^{-}⟶\mathrm{V};E^{\circ }=-1.19\mathrm{V}\\ & {\mathrm{Fe}}^{3+}(aq)+3e^{-}⟶\mathrm{Fe};{\mathrm{E}}^{\circ }=-0.04\mathrm{V}\\ & {\mathrm{Au}}^{3+}(aq)+3e^{-}⟶\mathrm{Au};E^{\circ }=+1.40\mathrm{V}\end{array}$$ $${\mathrm{Hg}}^{2+}(aq)+2e^{-}⟶\mathrm{Hg};E^{\circ }=+0.86\mathrm{V}$$ The pair(s) of metals that is (are) oxidised by ${\mathrm{NO}}_3^{-}$in aqueous solution is (are)