Chemistry - Electrochemistry Question with Solution | TestHub

Since ${\mathrm{NaNO}}_3$ is formed by the reaction $\mathrm{Nacl}+{\mathrm{KNO}}_3\to {\mathrm{NaNO}}_3+\mathrm{KCl}$ hence, using Kohlrausch's law $\begin{array}{rl}\stackrel{o}{\wedge }{\mathrm{m}}_{{\mathrm{NaNO}}_3}& ={\stackrel{o}{\wedge }}_{\mathrm{NaCl}}+{\stackrel{o}{\wedge }}_{{\mathrm{KNO}}_3}-{\stackrel{\circ }{\wedge }}_{\mathrm{KCl}}\\ & =128+111-152=87\mathrm{S}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}\end{array}$