Chemistry - Electrochemistry Question with Solution | TestHub

If the molar conductance values of ${\mathrm{Ca}}^{2+}$ and ${\mathrm{Cl}}^{-}$ at infinite dilution are respectively $118.88\times 10^{-4}$ ${\mathrm{m}}^2\mathrm{mh}{\mathrm{mol}}^{-1}$ and $77.33\times 10^{-4}{\mathrm{m}}^2\mathrm{mho}{\mathrm{mol}}^{-1}$ then that of ${\mathrm{CaCl}}_2$ is (in ${\mathrm{m}}^2{\mathrm{mhomol}}^{-1}$)