Chemistry - Electrochemistry Question with Solution | TestHub

Charge $=$ current $\times$ time Charge, $Q=1\mathrm{A}\times 60\sec$ $=60$ coulumb Now, 96500 C charge is carried by $6.023\times 10^{23}$ electron $$\begin{array}{rl}\Rightarrow 60\mathrm{C}\text{ charge }& =\frac{6.023\times 10^{23}}{96500}\times 60\text{ electrons }\\ & =3.74\times 10^{20}\text{ electrons }\end{array}$$