Select the most appropriate option about ligand considering below given reactions : (tu = thiourea)

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TestHub · Accepted Answer

Platinum(II) complexes typically exhibit a stable coordination number of 4 with a square planar geometry. In Reaction-1, the product formed with thiosulfate is $[Pt (S_{2} O_{3})_{2}]^{2 -}$ .

To maintain the coordination number of 4 with only two ligands present, each $S_{2} O_{3}^{2 -}$ must act as a bidentate ligand.

In contrast, $t u$ (thiourea) acts as a monodentate ligand in both reactions, forming $[Pt (t u)_{4}]^{2 +}$ and $t r an s - [Pt (N H_{3})_{2} (t u)_{2}]^{2 +}$ .

In Reaction-2, the thiosulfate product is $t r an s - [Pt (N H_{3})_{2} (O H_{2}) (S_{2} O_{3})]$ , where $S_{2} O_{3}^{2 -}$ acts as a monodentate ligand.

Chemistry - Coordination Chemistry Question with Solution | TestHub

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