Chemistry - Coordination Chemistry Question with Solution | TestHub
Column - I | Column - II | Column-III |
|---|---|---|
(a) | (i) Inner orbital complex | (P)Total possible isomers = 3 |
(b) | (ii) Low spin complex | (Q)Total possible isomers = 6 |
(c) | (iii) Outer orbital complex | (R) Total possible isomers = 8 |
(d) | (iv) High spin complex | (S) Total possible isomers = 10 |
.
Select CORRECT combination in which maximum number of unpaired electrons present in complex :
Options:
Answer:
Solution:
Complex (d) contains Ni²⁺, which has a electronic configuration.
With the weak field ligand SCN⁻, it forms an outer orbital complex (sp³d² hybridization) with 2 unpaired electrons.
Complexes (a), (b), and (c) all have strong field ligands or heavy metals (Pt⁴⁺), resulting in completely paired electrons (0 unpaired electrons).
Therefore, complex (d) possesses the maximum number of unpaired electrons, making combination d-iii-S the correct choice.
