For octahedral [Rh(ox)ₓ(NH₃) y ] ( 3 − 2 x ) , require 2x+y = 6. ox²⁻ is an achiral symmetrical chelate; ignore conformations. Which statement is INCORRECT?

Question

TestHub · Accepted Answer

x = 1 gives M(AA)a₄. The chelate occupies adjacent sites and the remaining donors are identical, so there is only one form. x = 2 gives an achiral trans form and a cis enantiomeric pair. x = 3 gives Δ/Λ. x = 0 is achiral Ma₆. First enforce the donor-count equation; counting oxalate as monodentate gives spurious forms.

Chemistry - Coordination Chemistry Question with Solution | TestHub

Options:

Doubts & Discussion