Chemistry - Coordination Chemistry Question with Solution | TestHub
ChemistryCoordination ChemistryIsomerismHard2 minQB
ChemistryHardinteger
The octahedral complex [Co(en)(NH₃)₂(NO₂)(SCN)]⁺ has two ambidentate ligands, NO₂⁻ (N or O) and SCN⁻ (S or N). Find the total number of isomers, counting both linkage forms and stereoisomers.
Answer:
24
Solution:
The two ambidentate ligands give 2 × 2 = 4 linkage forms. In each form the complex is M(AA)b₂cd, which has 4 geometrical and 6 stereoisomers. Total = 4 × 6 = 24.
Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Isomerism
⏱ 2mℹ️ Source: QB
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