Chemistry - Coordination Chemistry Question with Solution | TestHub
ChemistryCoordination ChemistryIsomerismHard2 minQB
ChemistryHardsingle choice
The total number of linkage isomers of the square-planar complex [Pd(SCN)₄]²⁻ (counting the all-S and all-N forms once each) plus those of the tetrahedral complex [Zn(SCN)₄]²⁻ is
Options:
Answer:
C
Solution:
Square planar with four ambidentate ligands: 0 N-bonded: 1; 1 N-bonded: 1; 2 N-bonded: cis and trans = 2; 3 N-bonded: 1; 4 N-bonded: 1; total 6. Tetrahedral: 0 to 4 N-bonded gives 5, with no geometrical isomers. Sum = 11.
Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Isomerism
⏱ 2mℹ️ Source: QB
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