Chemistry - Coordination Chemistry Question with Solution | TestHub

Given complex: $[RhH(C\equiv C–R{)}_2(PM{e}_3{)}_3{]}^0$

Oxidation state of Rh:

H = $-1$, each alkynyl $(C\equiv C–R)=-1$, PMe₃ = $0$

Let Rh = $x$

$x-1-2=0\Rightarrow x=+3$ → (A) correct

Metal–carbon linkages:

Two alkynyl ligands → 2 Rh–C bonds→ (B) correct

Isomerism:

Octahedral type arrangement gives restricted arrangements of ligands → multiple geometrical possibilities (cis/trans-type arrangements among similar ligands) → (D) correct

So correct options are: A, B, D

(Option C is incorrect)