Number of complex compounds from given below which have more number of valence electrons in the orbital of each central metal as compared to the number of valence electrons on central metal in [ Mn (

Question

Number of complex compounds from given below which have more number of valence electrons in the orbital of each central metal as compared to the number of valence electrons on central metal in [ Mn ( CO ) 5 ​ ] complex. Mn 2 ​ ( CO ) 10 ​ , [ Fe ( CO ) 5 ​ ] , [ Ni ( CO ) 4 ​ ] , Co 2 ​ ( CO ) 8 ​ , Fe 2 ​ ( CO ) 9 ​

TestHub · Accepted Answer

Reference Count: In the reference complex $[M n (CO)_{6}]^{+}$ , Manganese is in the +1 oxidation state (Mn⁺), giving it a $d^{6}$ configuration (6 valence electrons belonging strictly to the metal center).

Evaluation: We compare the valence electrons of each central metal atom in its ground oxidation state (0) for the remaining given neutral complexes:

$M n_{2} (CO)_{10} \to M n (0) = d^{7}$ (7 > 6)

$[F e (CO)_{5}] \to F e (0) = d^{8}$ (8 > 6)

$[N i (CO)_{4}] \to N i (0) = d^{10}$ (10 > 6)

$C o_{2} (CO)_{8} \to C o (0) = d^{9}$ (9 > 6)

$F e_{2} (CO)_{9} \to F e (0) = d^{8}$ (8 > 6)

Conclusion: All 5 given complexes have more valence electrons on their individual central metal centers than the reference complex.

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