Chemistry - Coordination Chemistry Question with Solution | TestHub

The complex is $[\mathrm{Mn}({\mathrm{NH}}_3{)}_6{]}^{2+}$.

Manganese is in the $+2$ oxidation state: ${\mathrm{Mn}}^{2+}$ has a $3{\mathrm{d}}^5$ configuration.

${\mathrm{NH}}_3$ is a strong field ligand, but for $3{\mathrm{d}}^5$${\mathrm{Mn}}^{2+}$, it acts as a weak field ligand, leading to a high-spin complex.

This means ${\Delta }_0<P$ (crystal field splitting energy is less than pairing energy).

The electronic configuration is $t_{2g}^3{e}_g^2$. There are 5 unpaired electrons.

The hybridization is ${\mathrm{sp}}^3{\mathrm{d}}^2$ (outer orbital complex).

Axial d-orbitals ($d_{z^2}$ and $d_{x^2-y^2}$) each contain one unpaired electron.

Final Answer: The final answer is $\boxed{A,B}$.