Chemistry - Coordination Chemistry Question with Solution | TestHub

Coordination Rule: Oxalate ($o{x}^{2-}$) is bidentate and H₂O is monodentate, so the total coordination number is given by $2x+y=6$.

For Statement (A): When $x=3,y=0$, the complex is $[Fe(ox{)}_3{]}^{3-}$, which is an $[M(AA{)}_3]$ type that lacks a plane of symmetry, making it optically active with no geometrical isomers.

For Statement (B): When $x=1,y=4$, the complex is $[Fe(ox)(H_{2}O{)}_4{]}^{+}$, which is an $[M(AA)b_4]$ type; it has only one symmetric spatial arrangement and cannot show geometrical or optical isomerism.

For Statement (C): When $x=2,y=2$, the complex is $[Fe(ox{)}_2(H_{2}O{)}_2{]}^{-}$, which exhibits both geometrical (cis and trans) and optical isomerism (in the cis-form).