Chemistry - Coordination Chemistry Question with Solution | TestHub

ChemistryCoordination ChemistryIsomerismHard2 minQB
ChemistryHardinteger

In the scheme, (AA) is a symmetrical achiral bidentate ligand, and b, c, d are achiral monodentate ligands. P is [M(AA)b₂c₂]. In step 1 the chelate opens to give two d ligands. In step 2 both b and both d are replaced by two (AA) ligands. X, Y and Z are the numbers of geometrical isomers of P, Q and R. They are the first, second and third digits of the answer XYZ.

Answer:
352
Solution:

P = M(AA)b₂c₂ has 3 geometrical isomers, so X = 3. Q = Mb₂c₂d₂ has 5, so Y = 5. R = [M(AA)₂c₂] has 2 (cis and trans), so Z = 2. Answer 352.

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Isomerism
⏱ 2mℹ️ Source: QB

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