Find the number of the paramagnetic and inner orbital complex in the following :- [ Ni ( CO ) 4 ] , [ Ni ( CN ) 4 ] 2 − , [ Co ( H 2 O ) 6 ] 3 + , [ Cu ( NH 3 ) 4 ] 2 + , [ Cr ( NH 3 ) 6

Question

Find the number of the paramagnetic and inner orbital complex in the following :- [ Ni ( CO ) 4 ​ ] , [ Ni ( CN ) 4 ​ ] 2 − , [ Co ( H 2 ​ O ) 6 ​ ] 3 + , [ Cu ( NH 3 ​ ) 4 ​ ] 2 + , [ Cr ( NH 3 ​ ) 6 ​ ] 3 + , [ Fe ( CN ) 6 ​ ] 3 −

TestHub · Accepted Answer

[Ni(CO)₄]: Ni(0) → d¹⁰, no unpaired electron → diamagnetic, inner orbital.

[Ni(CN)₄]²⁻: Ni(II) → d⁸, CN⁻ strong ligand, pairing occurs → diamagnetic, inner orbital (dsp²).

[Co(H₂O)₆]³⁺, [Cu(NH₃)₄]²⁺, [Cr(NH₃)₆]³⁺, [Fe(CN)₆]³⁻ show paramagnetic/outer orbital nature according to their d-electron configuration.

Paramagnetic inner orbital complexes are:

[Cu(NH₃)₄]²⁺, [Cr(NH₃)₆]³⁺, [Fe(CN)₆]³⁻

Hence, the total number = 3.

Chemistry - Coordination Chemistry Question with Solution | TestHub

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