Chemistry - Coordination Chemistry Question with Solution | TestHub
ChemistryCoordination ChemistryVBT,CFT(complex compound)Easy2 minQB
ChemistryEasyinteger
Treat NO as NO⁺, H₂O as weak-field and NH₃ as strong-field. Let X be the number of electrons in the orbitals of [Ru(NO)(NH₃)₅]³⁺, and Y be the number of electrons in the orbitals of [Cr(NO)(H₂O)₅]²⁺. Find X − Y.
Answer:
3
Solution:
In [Ru(NO)(NH₃)₅]³⁺, Ru is +2 (d⁶) and low spin, so ⁶, X = 6. In [Cr(NO)(H₂O)₅]²⁺, Cr is +1 (d⁵) and weak-field, so ³², Y = 3. X − Y = 3.
Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:VBT,CFT(complex compound)
⏱ 2mℹ️ Source: QB
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