Calculate the number of incorrect statements. (1) The hybridization of [ Cu ( NH 3 ) 4 ] 2 + is sp 3 (2) Among [ Co ( NH 3 ) 6 ] 3 + , [ I r ( N H 3 ) 6 ] 3 + , [ F e ( N H 3 ) 6 ] 3 +

Question

Calculate the number of incorrect statements. (1) The hybridization of $[Cu (NH_{3})_{4}]^{2 +}$ is $sp^{3}$

(2) Among $[Co (NH_{3})_{6}]^{3 +}, [I r (N H_{3})_{6}]^{3 +}, [F e (N H_{3})_{6}]^{3 +}$

the Δ₀ is highest for $[I r (N H_{3})_{6}]^{3 +}$

(3) NH₃ is a π -acceptor ligand

(4) CN^- is a σ donor as well as π acceptor ligand

(5) K₃[CoF₆] is paramagnetic whereas K₂[NiF₆] is diamagnetic

TestHub · Accepted Answer

Statement (1) is incorrect because [ C u ( N H 3 ​ ) 4 ​ ] 2 + has a square-planar geometry with d s p 2 hybridization, not s p 3 . Statement (2) is correct as crystal field splitting ( Δ 0 ​ ) increases down a group ( 5 d > 3 d ), making it highest for the 5 d metal ion I r 3 + . Statement (3) is incorrect because NH₃ is a classic σ -donor only and lacks vacant orbitals to act as a π -acceptor. Statements (4) and (5) are correct because CN⁻ undergoes π -backbonding, C o 3 + ( d 6 high-spin) is paramagnetic, and N i 4 + ( d 6 low-spin due to high charge) is diamagnetic.

Chemistry - Coordination Chemistry Question with Solution | TestHub

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