Consider the following complex compounds: (i) [ Pt ( N H 3 ) 2 ( SCN ) 2 ] (ii) [ C o ( N H 3 ) 3 ( N O 2 ) 3 ] (iii) [ Pt ( e n ) 2 C l 2 ] (iv) [ C r ( e n ) 2 B r 2 ] ⁺ (v) [

Question

Consider the following complex compounds:

(i) $[Pt (N H_{3})_{2} (SCN)_{2}]$

(ii) $[C o (N H_{3})_{3} (N O_{2})_{3}]$

(iii) $[Pt (e n)_{2} C l_{2}]$

(iv) $[C r (e n)_{2} B r_{2}]$ ⁺

(v) $[R h (e n)_{3}]$ ³⁺

(vi) $[C o C l_{2} B r_{2}]$ ²⁻

Then calculate the sum of the total number of geometrical isomers in all the above complex compounds.

TestHub · Accepted Answer

Complexes No. of geometrical isomers

(i) $[Pt (NH_{3})_{2} (SCN)_{2}]$ 2

(ii) $[Co (NH_{3})_{3} (NO_{2})_{3}]$ 2

(iii) $[Pt (e n) Cl_{2}]$ 0

(iv) $[Cr (e n)_{2} Br_{2}]^{+}$ 2

(v) $[R h (e n)_{3}]^{3 +}$ 0

(vi) $[CoCl_{2} Br_{2}]^{2 -}$ 0

Hence, sum of total number of geometrical isomers $= 6$ .

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