If the bidented ligand ethane1-2diamine(en) is progressively added to $[Ni (H_{2} O)_{6}]^{+ 2}$ in the molar ratio en : $[Ni (H_{2} O)_{6}]^{+ 2}; 1 : 1, 2 : 1, 3 : 1$ then complex form are $(P) (Q)$ and $(R)$ respectively.
Select INCORRECT statement for (P) (Q) and (R).

Question

If the bidented ligand ethane1-2diamine(en) is progressively added to $[Ni (H_{2} O)_{6}]^{+ 2}$ in the molar ratio en : $[Ni (H_{2} O)_{6}]^{+ 2}; 1 : 1, 2 : 1, 3 : 1$ then complex form are $(P) (Q)$ and $(R)$ respectively.

Select INCORRECT statement for (P) (Q) and (R).

TestHub · Accepted Answer

Ethane-1,2-diamine ( e n ) is a bi d e n t a t e l i g an d and forms chelate rings with Ni²⁺. Complexes formed are: P: [ N i ( e n ) ( H 2 ​ O ) 4 ​ ] 2 + Q: [ N i ( e n ) 2 ​ ( H 2 ​ O ) 2 ​ ] 2 + R: [ N i ( e n ) 3 ​ ] 2 + All have Ni²⁺, coordination number = 6, and EAN = 38. They contain N i – N an d N i – Ol inka g es , but geometrical isomerism is not possible for all (especially R). Hence, the incorrect statement is: (C) All have Ni–O linkages and geometrical isomers

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