For a d⁶ octahedral ion, the splitting energy is Δₒ = 21000 cm⁻¹ and the mean pairing energy is P = 19000 cm⁻¹. Take the stabilisation energy as −0.4Δₒ for the high-spin state and −2.4Δₒ + 2P for the

Question

For a d⁶ octahedral ion, the splitting energy is Δₒ = 21000 cm⁻¹ and the mean pairing energy is P = 19000 cm⁻¹. Take the stabilisation energy as −0.4Δₒ for the high-spin state and −2.4Δₒ + 2P for the low-spin state (the extra pairing relative to high spin included). Find the magnitude of the difference between the two values in cm⁻¹.

Answer:

4000

Solution:

High spin: −0.4 × 21000 = −8400. Low spin: −2.4 × 21000 + 2 × 19000 = −50400 + 38000 = −12400. The difference is 4000 cm⁻¹ in favour of low spin.

TestHub · Accepted Answer

High spin: −0.4 × 21000 = −8400. Low spin: −2.4 × 21000 + 2 × 19000 = −50400 + 38000 = −12400. The difference is 4000 cm⁻¹ in favour of low spin.

Chemistry - Coordination Chemistry Question with Solution | TestHub

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