Chemistry - Coordination Chemistry Question with Solution | TestHub

The total number of possible isomers for $[Pt(CN{)}_2(N{O}_2)(N{O}_3){]}^{2-}$ is 14 (Option C), calculated as follows:

Complex Type: Platinum(II) forms a square planar complex where CN⁻ and NO₂⁻ act as ambidentate ligands.

Linkage Combinations: The two cyano ligands can coordinate in three ways: $(C,C)$, $(N,N)$, or $(C,N)$, while NO₂⁻ can coordinate in two ways: $-N{O}_2$ or $-ONO$.

Symmetric Modes: For the $(C,C)$ and $(N,N)$ modes, each forms 2 geometrical isomers (cis and trans) with both $-N{O}_2$ and $-ONO$, yielding $2\times 2\times 2=8$ isomers.

Asymmetric Modes: For the $(C,N)$ mode, it acts like an $[MABCD]$ type complex, forming 3 geometrical isomers with both $-N{O}_2$ and $-ONO$, yielding $2\times 3=6$ isomers.

Total Isomers: Adding them together gives $8+6=14$ total isomers.