Find sum of missing digits x and y in given complexes Ba x [Pt IV (CN) 4 Cl 2 ] [Pt II (en) 2 ]Cl y

[Pt IV (CN) 4 Cl 2 ]: +4 - 4 - 2 = -2, so 2x = 2 and x = 1 (one Ba 2+ ). [Pt II (en) 2 ] has charge +2, so y = 2. x + y = 3.

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ChemistryCoordination ChemistryWerner theory + calculation of EANMedium2 minQB

ChemistryMediuminteger

Find sum of missing digits x and y in given complexes

Ba_x[Pt^IV(CN)₄Cl₂]

[Pt^II(en)₂]Cl_y

Answer:

Solution:

[Pt^IV(CN)₄Cl₂]: +4 - 4 - 2 = -2, so 2x = 2 and x = 1 (one Ba²⁺).

[Pt^II(en)₂] has charge +2, so y = 2.

x + y = 3.

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Werner theory + calculation of EAN

⏱ 2mℹ️ Source: QB

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