Chemistry - Coordination Chemistry Question with Solution | TestHub

Question Explanation:

Pair complexes with identical isomerism types.

Concept:

Identifying shared isomerism patterns.

Solution:

Pair 2: ${\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]}^{+}$(octahedral) and ${\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_2\left({\mathrm{H}}_2\mathrm{O}\right)\mathrm{Cl}\right]}^{+}$(square planar) both exhibit geometrical isomerism (cis/trans).

Pair 4: $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_3\left({\mathrm{NO}}_3\right)\right]\mathrm{Cl}$and $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_3\mathrm{Cl}\right]\mathrm{Br}$both exhibit ionization isomerism by exchanging internal ligands with external counter-ions.

Pair 1: These complexes have different coordination spheres and do not share a common isomerism type.

Pair 3:${\left[{\mathrm{CoBr}}_2{\mathrm{Cl}}_2\right]}^{2-}$is tetrahedral (no geometrical isomers), while ${\left[{\mathrm{PtBr}}_2{\mathrm{Cl}}_2\right]}^{2-}$is square planar (has geometrical isomers).

Final Answer: Options (B) and (D)