Chemistry - Coordination Chemistry Question with Solution | TestHub

Oxidation State Analysis: Zinc ($Zn$) retains its highly stable $+2$ oxidation state during oxidation because a $d^{10}$ configuration is extremely difficult to oxidize further, making option (A) incorrect.

Ligand Transformation: In the reactant $K_4[Zn(CN{)}_4(O_2{)}_2]$, the two peroxyl/dioxygen ligands exist as superoxide ions ($O_2^{-}$), which oxidize into neutral dioxygen molecules ($O_2$) in the product $K_2[Zn(CN{)}_4(O_2{)}_2]$.

Bond Length (B): The molecular orbital bond order increases from $1.5$ (for $O_2^{-}$) to $2.0$ (for $O_2$), causing the O–O bond length to decrease.

Magnetic Properties (C & D): The number of unpaired electrons increases from 2 (one per $O_2^{-}$) to 4 (two per $O_2$), which increases the magnetic moment, while the overall paramagnetic behavior remains unchanged.