Chemistry - Coordination Chemistry Question with Solution | TestHub

Stereoisomers: The complex ion $[Co(N{H}_3{)}_5(N{O}_2){]}^{2+}$ is of the $M{A}_{5}B$ type, which does not show geometrical or optical isomerism, meaning it has only 1 stereoisomer.

Structural Isomers: Due to the presence of the ambidentate $N{O}_2^{-}$ ligand and outer-sphere $N{O}_3^{-}$ ions, it forms 3 structural isomers:

$[Co(N{H}_3{)}_5(N{O}_2)](N{O}_3{)}_2$ (Nitro-linkage isomer)

$[Co(N{H}_3{)}_5(ONO)](N{O}_3{)}_2$ (Nitrito-linkage isomer)

$[Co(N{H}_3{)}_5(N{O}_3)](N{O}_2)(N{O}_3)$ (Ionization isomer)

Comparison: The number of stereoisomers (1) is less than the number of structural isomers (3) by exactly $3-1=2$.