Chemistry - Coordination Chemistry Question with Solution | TestHub

Solution for Complex 1: $B{a}_x[P{t}^{IV}(CN{)}_{4}C{l}_2]$

The oxidation state of Platinum ($Pt$) is given as $+4$.

The ligands consist of four $C{N}^{-}$ ($4\times -1$) and two $C{l}^{-}$ ($2\times -1$).

The total charge of the coordination sphere is $(+4)+(-4)+(-2)=-2$.

Since Barium ($Ba$) has a $+2$ charge, one atom is needed to neutralize the $-2$ sphere.

Thus, the value of $x=1$.

Solution for Complex 2: $[P{t}^{II}(en{)}_2]C{l}_y$

The oxidation state of Platinum ($Pt$) is given as $+2$.

Ethylenediamine ($en$) is a neutral ligand, so its contribution to the charge is $0$.

The total charge of the coordination sphere $[Pt(en{)}_2]$ is $(+2)+0=+2$.

To neutralize this, two Chloride ions ($C{l}^{-}$) with a $-1$ charge each are required.

Thus, the value of $y=2$.

Final Calculation:

The sum of the missing digits $x+y=1+2=3$.