Chemistry - Coordination Chemistry Question with Solution | TestHub

ChemistryCoordination ChemistryVBT,CFT(complex compound)Medium2 min

ChemistryMediumsingle choice

Passage / Comprehension

The octahedral complex ions $[FeCl_{6}]^{3 -}$ and $[F e (CN)_{6})]^{3 -}$ are both paramagnetic but the former is a high spin complex and the latter is a low spin complex.

Unpaired electron(s) in $[FeCl_{6}]^{3 -}$ and $[Fe (CN)_{6}]^{3 -}$ are respectively:

Options:

Answer:

Solution:

$\displaylines [F e C l_{6}]^{3 -}$

$C l^{-} \to$ WFL (unpaired electrons will be 5) no pairing

$C N^{-} \to$ SFL pairing will take place so unpaired electrons will be 1

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:VBT,CFT(complex compound)

⏱ 2m

Doubts & Discussion

Loading discussions...