Chemistry - Coordination Chemistry Question with Solution | TestHub

$\begin{array}{rl}& \\ & {\mathrm{K}}_3\left[\mathrm{Fe}(\mathrm{OH}{)}_6\right]\\ & {\mathrm{Fe}}^{3+}\Rightarrow 3{\mathrm{d}}^5\\ & {\mathrm{Fe}}^{3+}\text{ with }{\mathrm{OH}}^{-}(\mathrm{WFL})\\ & ={\mathrm{t}}_{29}{}^3{\mathrm{e}}_{\mathrm{g}}{}^2\end{array}$ Number of unpaired electron ( $n$ ) $=5$ $\mu$ spin only $=5.92\mathrm{BM}$ $\begin{array}{rl}& {\mathrm{K}}_4\left[\mathrm{Fe}(\mathrm{OH}{)}_6\right]\\ & {\mathrm{Fe}}^{2+}\Rightarrow {\mathrm{OH}}^{-}(\mathrm{WFL})\\ & {\mathrm{Fe}}^{2+}\Rightarrow 3{\mathrm{d}}^6={\mathrm{t}}_{2\mathrm{g}}^4{\mathrm{e}}_{\mathrm{g}}^2\\ & \mathrm{n}=4\end{array}$ ${\mu }_{\text{spin only }}=4.90\mathrm{BM}$