The correct order of the number of unpaired electrons in the given complexes is
(A) $[Fe (CN)_{6}]^{3 -}$
(B) ${[{FeF}_{6}]}^{3 -}$
(C) ${[{CoF}_{6}]}^{3 -}$
(D) ${[Cr (oxalate)_{3}]}^{3 -}$
(E) $[Ni (CO)_{4}]$
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Question

The correct order of the number of unpaired electrons in the given complexes is

(A) $[Fe (CN)_{6}]^{3 -}$

(B) ${[{FeF}_{6}]}^{3 -}$

(C) ${[{CoF}_{6}]}^{3 -}$

(D) ${[Cr (oxalate)_{3}]}^{3 -}$

(E) $[Ni (CO)_{4}]$

Choose the correct answer from the options given below:

TestHub · Accepted Answer

The number of unpaired electrons in coordination complexes is determined by the nature of the central metal ion, the coordination number, and the identity and arrangement of the ligands around the metal ion. Based on these factors, the correct order of the number of unpaired electrons in the given complexes is:

A	${[Fe (CN)_{6}]}^{3 -}$ $: {Fe}^{3 +} (3 d^{5})$ (Pairing of electrons takes place)	$1$
B	${[{FeF}_{6}]}^{3 -}$ $: {Fe}^{3 +} (3 d^{5})$	$5$
C	${[{CoF}_{6}]}^{3 -}$ $: {Co}^{3 +} (3 d^{6})$	$4$
D	${[Cr (oxalate)_{3}]}^{3 -}$ $: {Cr}^{3 +} (3 d^{3})$	$3$
E	$[Ni (CO)_{4}]$ $: Ni (3 d^{10})$ (Pairing of electrons takes place)	$0$

No. of unpaired electrons order: $E < A < D < C < B$

Chemistry - Coordination Chemistry Question with Solution | TestHub

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