Chemistry - Coordination Chemistry Question with Solution | TestHub

${\mathrm{K}}_3\left[\mathrm{F}\mathrm{e}\right(\mathrm{C}\mathrm{N}{)}_6]$

Electronic configuration of$\mathrm{F}\mathrm{e}=\left[\mathrm{A}\mathrm{r}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^6$

Electronic configuration of$\mathrm{F}{\mathrm{e}}^{+3}=\left[\mathrm{A}\mathrm{r}\right]3{\mathrm{d}}^5$

Number of ligand (coordination numbr)$=6$

Nature of ligand is strong field.



Hybridization of$\mathrm{F}\mathrm{e}$is${\mathrm{d}}^2\mathrm{s}{\mathrm{p}}^3$.