Chemistry - Coordination Chemistry Question with Solution | TestHub

${\left[\text{Pt}{\left({\text{NH}}_{\text{3}}\right)}_{\text{4}}{\text{Cl}}_{\text{2}}\right]}^{\text{2+}}$has$\text{2}$geometrical isomers.

${\left[\text{Pt}{\left(\text{gly}\right)}_{\text{3}}\right]}^{\text{2}-}$will have$2$geometrical isomers, both of which will be optical active, giving a total of$4$isomers.

${\left[\text{Pt}{\left(\text{en}\right)}_{\text{3}}\right]}^{\text{4+}}$will have no geometrical isomers, but the compound will be optically active, hence total two isomers.

$\left[\text{Pt}{\left({\text{NH}}_{\text{3}}\right)}_{\text{2}}{\text{Cl}}_{\text{2}}\right]$will have two geometrical isomers.