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ChemistryCoordination ChemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The crystal field splitting energy (CFSE) for ${[C o C l_{6}]}^{4 -}$ is about 18000 $c m^{- 1}$ . What would be the CFSE value for $[C o C l_{4}]^{2 -}$ ?

Answer:

8000.00

Solution:

CFSE $(Δ_{0})$ of $[C o C l_{6}]^{4 -} = 18000 c m^{- 1}$

CFSE $(Δ_{t})$ of $[C o C l_{4}]^{2 -} = ?$

From formula, $Δ_{t} = \frac{4}{9} \times Δ_{0}$

$= \frac{4}{9} \times 18000 c m^{- 1}$

$= 8000 c m^{- 1}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Coordination ChemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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