Chemistry - Coordination Chemistry Question with Solution | TestHub

$\left(\mathrm{a}\right)$$\text{Ni}(\text{CO}{)}_4$

$\text{Ni}={\text{3d}}^{10}{\text{4s}}^0\left[\text{S F L}\right]\text{ ;}\text{μ}=0$

$\left(\mathrm{b}\right)$$[\text{Ni}\left({\mathrm{H}}_2\mathrm{O}{)}_6\right]\text{C}{\text{l}}_2$

${\text{Ni}}^{2+}={\text{3d}}^8$

Weak field ligand



No. of unpaired electron$=2$

$\mathrm{\mu }=\sqrt{\mathrm{n}\left(\mathrm{n}+2\right)}=\sqrt{2\left(2+2\right)}=\sqrt{8}\mathrm{ }\mathrm{B}.\mathrm{M}$

$\left(\mathrm{c}\right)$$\text{N}{\text{a}}_2[\text{Ni}\left(\text{CN}{)}_4\right]$

$\text{N}{\text{i}}^{2+}–\text{3}{\text{d}}^8\left(\text{S F L}\right)$

pairing take place (n = 0)

$\mathrm{\mu }=0$

$\left(\mathrm{d}\right)$$\text{PdC}{\text{l}}_2{\left(\text{PP}{\text{h}}_3\right)}_2$

$\text{P}{\text{d}}^{2+}=\text{4}{\text{d}}^8$

square planar

$\mathrm{\mu }=0$