Chemistry - Coordination Chemistry Question with Solution | TestHub

$\mathrm{\mu }=\sqrt{\mathrm{n}(\mathrm{n}+2)}\hspace{0.33em}\mathrm{B}\mathrm{M}$, n is number of unpaired electrons.

$\left[\mathrm{F}\mathrm{e}\right({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{2+}$has four unpaired electrons,$\left[\mathrm{C}\mathrm{r}\right({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{3+},\left[\mathrm{C}\mathrm{u}\right({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{2+}$and$\left[\mathrm{Z}\mathrm{n}\right({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{2+}$have 3, 1, 0 unpaired electrons respectively.