Chemistry - Coordination Chemistry Question with Solution | TestHub

Compound${\left[\mathrm{C}\mathrm{o}\mathrm{C}\mathrm{l}{\left(\mathrm{e}\mathrm{n}\right)}_2\right]}^{+}$
Since$\mathrm{C}{\mathrm{l}}^{-}$is monodentate ligand, en$\to \mathrm{ }$bidentate ligand
Co-ordination number$=1+2\times 2=5$
Compound${\left[\mathrm{C}\mathrm{o}{\left({\mathrm{C}}_2{\mathrm{O}}_4\right)}_3\right]}^{3-}$
$\mathrm{O}{\mathrm{X}}^{2-}\to$bidentate ligand co-ordination number$=\mathrm{ }3\mathrm{ }\times \mathrm{ }2\mathrm{ }=\mathrm{ }6$