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Chemistry - Coordination Chemistry Question with Solution | TestHub

ChemistryCoordination ChemistryIntroduction, About ligandEasy2 minPYQ_2019

ChemistryEasysingle choice

The coordination number of Th in $K_{4} [Th (C_{2} O_{4})_{4} (H_{2} O)_{2}]$ is: $(C_{2} O_{4}^{2 -} =$ oxalato $)$

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Solution:

$K_{4} [Th (C_{2} O_{4})_{4} (H_{2} O)_{2}]$ $C_{2} O_{4}^{2 -}$ (oxalato) : bidentate ligand $H_{2} O$ (aqua): monodentate $∴$ Co-ordination no. of Th $= 2 \times 4 + 2 = 10$

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Introduction, About ligand

⏱ 2mℹ️ Source: PYQ_2019

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