Among the species given below, the total number of diamagnetic species is ___.
$H a t o m, N O_{2} m o n o m e r, O_{2}^{-}$ (superoxide), dimeric sulphur in vapour phase, $M n_{3} O_{4}, {(N H_{4})}_{2} [F e C l_{4}], {(N H_{4})}_{2} [N i C l_{4}], K_{2} M n O_{4}, K_{2} C r O_{4}$

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TestHub · Accepted Answer

H - atom = paramagnetic N O 2 = odd unpaired electron species paramagnetic O 2 - (superocide) = One unpaired electrons in π * M.O. paramagnetic S 2 (in vapour phase) = same as O 2 , two unpaired e - s are present in π * M.O. paramagnetic

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