Chemistry - Coordination Chemistry Question with Solution | TestHub

${\left[\mathrm{Ni}(\mathrm{CN}{)}_4\right]}^{2-}$ is square planar, diamagnetic $(0$ unpaired electrons) with $ds{p}^2$ hybridisation. $\left[\mathrm{Ni}(\mathrm{CO}{)}_4\right]$ - is tetrahedral,diamagnetic ( $0$ unpaired electrons) with $s{p}^3$ hybridisation. ${\left[{\mathrm{NiCl}}_4\right]}^{2-}$ is tetrahedral, paramagnetic ($2$ unpaired electrons) with $s{p}^3$ hybridisation. Hence, the option (c) is the correct answer.