Chemistry - Coordination Chemistry Question with Solution | TestHub

Electronic configuration of $\mathrm{Fe}=\left[\mathrm{Ar}\right]4 {\mathrm{s}}^{2}3 {\mathrm{d}}^6$ ${\mathrm{Fe}}^{2+}=\left[\mathrm{Ar}\right]3{\mathrm{d}}^6$

${\mathrm{CN}}^{-}$ are strong field ligands

${\mathrm{d}}^2{\mathrm{sp}}^3$ hybridisation

$\because {\mathrm{CN}}^{-}$ is a strong ligand and from six coordinate bonds with ${\mathrm{Fe}}^{3+}$ . Thus $\mathrm{Fe}$ show ${\mathrm{d}}^2{\mathrm{sp}}^3$ hybridisation in ${\mathrm{K}}_3\mathrm{Fe}(\mathrm{CN}{)}_6$.