Chemistry - Coordination Chemistry Question with Solution | TestHub

More be the number of unpaired electrons $\to$ more be the magnetic moment.

and

Number of unpaired electrons in ${\mathrm{Mg}}^{2+}=0$

Number of unpaired electrons in ${\mathrm{Ti}}^{3+}=1$

Number of unpaired electrons in ${\mathrm{V}}^{3+}=2$

${\mathrm{Fe}}^{2+}=4$

Number of unpaired electrons in

Thus, ${\mathrm{Fe}}^{2+}$ show maximum value of magnetic moment $\left(\mathrm{\mu }\right)$.

also, $\mathrm{\mu }=\sqrt{\mathrm{n}(\mathrm{n}+2)}$. $BM$ ($\mathrm{n}=$ Number of unpaired electrons).