Chemistry - Coordination Chemistry Question with Solution | TestHub

$\mathrm{mmol}$ of complex $=30\times 0.01=0.3$ Also, 1 mole of complex $\left[\mathrm{Cr}{\left({\mathrm{H}}_2\mathrm{O}\right)}_5\mathrm{Cl}\right]{\mathrm{Cl}}_2$ gives only two moles of chloride ion when dissolved in solution $$\left[\mathrm{Cr}{\left({\mathrm{H}}_2\mathrm{O}\right)}_5\mathrm{Cl}\right]{\mathrm{Cl}}_2⟶[\mathrm{Cr}{\left({\mathrm{H}}_2\mathrm{O}\right)}_5{\mathrm{Cl}}^{2+}+2{\mathrm{Cl}}^{-}$$ $\Rightarrow \mathrm{mmol}$ of ${\mathrm{Cl}}^{-}$ion produced from its $0.3\mathrm{mmol}=0.6$ Hence, $0.6\mathrm{mmol}$ of ${\mathrm{Ag}}^{+}$would be required for precipitation. $$\begin{array}{rl}& \Rightarrow 0.60\mathrm{mmol}\text{ of }{\mathrm{Ag}}^{+}=0.1\mathrm{M}\times \mathrm{V}(\text{ in }\mathrm{mL})\\ & \Rightarrow V=6\mathrm{mL}.\end{array}$$