Match the list : (Assume CaCO 3 is water soluble) List - I (Concentration of aqueous solution) List - II (Density of given solutions is 1.2 g/ml) (P) 2 M NaOH solution (1) 16gm solute in 240gm solut

Question

Match the list : (Assume CaCO 3 ​ is water soluble) List - I (Concentration of aqueous solution) List - II (Density of given solutions is 1.2 g/ml) (P) 2 M NaOH solution (1) 16gm solute in 240gm solution (Q) 8% ( V w ​ ) KOH solution (2) 60gm solute in 240 gm solution (R) 25% ( W W ​ ) CaCO 3 ​ solution (3) 8gm solute in 100 ml solution (S) X C 3 ​ H 7 ​ OH ​ = 11 1 ​ (4) 30 gm solute in 100 ml solution (5) 1 mole solute in 400 gm solution The correct match is :

TestHub · Accepted Answer

(P) 2M aq. NaOH solution ( d = 1.2 gm / ml ) 2 moles NaOH present in 11 ( 1000 ml ) solution or 2 moles NaOH ( 80 gm ) in 1200 gm solution 1000 ml solution → 80 gm NaOH 100 ml solution → 8 gm NaOH 1200 gm solution → 80 gm 240 gm solution → 1200 80 ​ × 240 = 16 gm NaOH (Q) 8% ( W W ​ ) aq. KOH (d = 1.2 gm/mol) 8 gm KOH in 100 ml solution 8 gm KOH in 120 gm solution 16 gm KOH in 240 gm solution (R) 25% ( W W ​ ) CaCO 3 ​ solution ( d = 1.2 gm / ml ) 100 gm solution contains 25 gm CaCO₃ 400 gm solution → 100 gm (1 mole) CaCO₃ 240 gm solution → 100 25 ​ × 240 = 60 gm CaCO 3 ​ 1.2 100 ​ m l so l u t i o n → 25 g m C a C O 3 ​ (S) X C 3 ​ H 7 ​ OH ​ = 11 1 ​ = 1 + 10 1 ​ : i.e. 240 gm solution = 200 ml solution

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Doubts & Discussion

List - I (Concentration of aqueous solution)	List - II (Density of given solutions is 1.2 g/ml)
(P) 2 M NaOH solution	(1) 16gm solute in 240gm solution
(Q) $8% (\frac{w}{V})$ KOH solution	(2) 60gm solute in 240 gm solution
(R) $25% (\frac{W}{W}) CaCO_{3}$ solution	(3) 8gm solute in 100 ml solution
(S) $X_{C_{3} H_{7} OH} = \frac{1}{11}$	(4) 30 gm solute in 100 ml solution
	(5) 1 mole solute in 400 gm solution