Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minQB

ChemistryMediuminteger

When 20 mL of pure acetic acid (density = 0.75 g mL⁻¹) is mixed with 50 g of water (density = 1 g mL⁻¹) at a certain temperature, calculate the molality of acetic acid in the final solution.

Answer:

Solution:

Mass of acetic acid = $0.75 \times 20 = 15 g$

Mass of water = $50 g$

$m = \frac{15 \times 1000}{60 \times 50} = 5 m o l a l$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: QB

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